SQL SERVER - occupazione Tabelle

Ecco una query che mostra l'occupazione fisica di tabelle in un database specifico:


[code] use DATABASE_NAME SELECT t.NAME AS TableName, s.Name AS SchemaName, p.rows AS RowCounts, SUM(a.total_pages) * 8 AS TotalSpaceKB, SUM(a.used_pages) * 8 AS UsedSpaceKB, (SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB FROM sys.tables t INNER JOIN sys.indexes i ON t.OBJECT_ID = i.object_id INNER JOIN sys.partitions p ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id INNER JOIN sys.allocation_units a ON p.partition_id = a.container_id LEFT OUTER JOIN sys.schemas s ON t.schema_id = s.schema_id WHERE t.NAME NOT LIKE 'dt%' AND t.is_ms_shipped = 0 AND i.OBJECT_ID > 255 GROUP BY t.Name, s.Name, p.Rows ORDER BY t.Name [/code]  otterrete lo spazio occupato in KB. Molto comoda per quando in un database di grandi dimensioni è necessario scovare la tabella di più grandi dimensioni